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Friday, 13 December 2019

Program to find Minimum and Maximum number in an Array

import java.util.Scanner;

class rkmin
 {
  public static void main(String x[])
  {
   int i,p=0,q=0,n,min,max;
   Scanner s=new Scanner(System.in);
   System.out.println("Enter Size Of Array :");
   n=s.nextInt();
   int[] a;//declaration of array
   a=new int[n]; // Creation of array with given size
  for(i=0;i<n;i++)
    {
     System.out.printf("\n Element a[%d]  :",i);
     a[i]=s.nextInt();
    }
   System.out.print("\n Array elements :");
   for(i=0;i<n;i++)
    {
     System.out.print(a[i]+" ");
    }
   for(i=0;i<n;i++)
    {
     System.out.printf("\n ADDRESS=%h ---- ARRAY=a[%d] DATA=%d\n",i*4,i,a[i]);
    }
    min=a[0];
    max=a[0];
   for(i=0;i<n;i++)
    {
    if(a[i]>max)
    {max=a[i]; p=i;}

   if(a[i]<min)
     {min=a[i];q=i;}
    }

   System.out.println("\n maximum number is :" +max+ " and " + "minimum number is :"+min);

//    System.out.println("minimum number is :"+min);

   for(i=0;i<n;i++)
   {
    if(a[i]==max)
     System.out.printf("\n ADDRESS=%h ---- ARRAY=a[%d] DATA=%d\n",i*4,i,a[i]);
    if(a[i]==min)
     System.out.printf("\n ADDRESS=%h ---- ARRAY=a[%d] DATA=%d\n",i*4,i,a[i]);
   }
  }
}

output:

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